*This is an answer I found elsewhere on Brainly.*
(4+√10)(4-√10)
=16-4√10+4√10-10
=6
------------------------------
(4+√10)+(4-√10)
=4+√10+4-√10
=8
----------------------------
The numbers are:
4+√10, and 4-√10
Answer:
The toy airplane costs $72 more than the toy motorcycle. Hope this helps!
Step-by-step explanation:
$24 x 4 = $96
$96 - $24 = $72.
Each side of cube is 100 cm.
<h3>What is a cube?</h3>
In Maths or in Geometry, a Cube is a solid three-dimensional figure, which has 6 square faces, 8 vertices and 12 edges. It is also said to be a regular hexahedron.
Given that,
Volume of cube = 1 cubic meter
We know that,
1 m = 100 cm
Also volume of cube = ![a^{3}](https://tex.z-dn.net/?f=a%5E%7B3%7D)
Then,
Volume of cube = 1000000 cm
= ![100^{3}](https://tex.z-dn.net/?f=100%5E%7B3%7D)
a = 100 cm
Hence, Each side of cube is 100 cm.
To learn more about cube from the given link:
brainly.com/question/1972490
#SPJ4
Answer:
A sample of 385 is needed.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1 - 0.95}{2} = 0.025](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1%20-%200.95%7D%7B2%7D%20%3D%200.025)
Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.96.
Now, find the margin of error M as such
![M = z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population, which is the square root of the variance, and n is the size of the sample.
Assume the variance is known to be 3.61.
This means that ![\sigma = \sqrt{3.61}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B3.61%7D)
How large of a sample would be required in order to estimate the mean number of reproductions per hour at the 95% confidence level with an error of at most 0.19 reproductions?
A sample of n is needed.
n is found when
. So
![M = z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![0.19 = 1.96\frac{\sqrt{3.61}}{\sqrt{n}}](https://tex.z-dn.net/?f=0.19%20%3D%201.96%5Cfrac%7B%5Csqrt%7B3.61%7D%7D%7B%5Csqrt%7Bn%7D%7D)
![0.19\sqrt{n} = 1.96\sqrt{3.61}](https://tex.z-dn.net/?f=0.19%5Csqrt%7Bn%7D%20%3D%201.96%5Csqrt%7B3.61%7D)
![\sqrt{n} = \frac{1.96\sqrt{3.61}}{0.19}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B1.96%5Csqrt%7B3.61%7D%7D%7B0.19%7D)
![(\sqrt{n})^2 = (\frac{1.96\sqrt{3.61}}{0.19})^2](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E2%20%3D%20%28%5Cfrac%7B1.96%5Csqrt%7B3.61%7D%7D%7B0.19%7D%29%5E2)
![n = 384.16](https://tex.z-dn.net/?f=n%20%3D%20384.16)
Rounding up
A sample of 385 is needed.
The whole is 10/10 (consider to use the same denominator when comparing fractions) The half of 10/10 will be 5/10 which is not 4/10.
it's close to half but not the half