The surface area of a pyramid may be calculated using the formula: Area = length * width + length*√[(width/2)² + height²] + width*√[(length/2)² + height²]
In this case, the base of the pyramid is a square, which means that the length and the width are equivalent. Therefore, the equation simplifies: Area = l² + 2l√[(l/2)² + h²]
Now, we substitute the values into the equation: A = 10² + 2*10*√[(10/2)² + 12²] A = 360
The surface area of the pyramid is 360 square inches.
The pyramid is shown in the diagram below. The pyramid is built from four congruent triangles and one square as the base
We have the side of the square, so the area is = 10×10 = 100
We need the height of the triangle to work out its area. We can find out by using the height of the pyramid and half of the length of the side of the square.
Using the Pythagoras rule Height of triangle =
Area of one triangle = 1/2×10×12=60 Surface area of the pyramid = 100 + (4×60) = 340 square inches
C. The answer is C because the total amount of students is 14, and there are 4 boys, which makes the ratio 4 boys to 14 students in total. 4 and 14 are both divisable by 2, so divide 4 to get 2 and divide 14 to get 7. This leaves you with 2 and 7. The ratio would be 2 boys to 7 total students. Hope this helped