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Gre4nikov [31]
2 years ago
13

the straight line L has the equation 4y=5x+3. Point A has the coordinates (3,-2) Find the equation of the line straight line tha

t is perpendicular to L and passes through A. Write your answer in the form y-mx+c where m and c are decimals or fractions {3 marks}
Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
4 0

Answer:

y = - \frac{4}{5} x + \frac{2}{5}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 4y = 5x + 3 into this form by dividing the 3 terms by 4

y = \frac{5}{4} x + \frac{3}{4} ← in slope- intercept form

with slope m = \frac{5}{4}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{5}{4} } = - \frac{4}{5} , thus

y = - \frac{4}{5} x + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = - \frac{12}{5} + c ⇒ c = - 2 + \frac{12}{5} = \frac{2}{5}

y = - \frac{4}{5} x + \frac{2}{5} ← equation of perpendicular line

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5 0
3 years ago
PLEASE HELP ASAP!!!!!
erastova [34]

Answer:

B = (3, 3)

Step-by-step explanation:

Since the line segment is fifteen units long, from the looks of it, chopping ⅓ of A's side, led to the ordered pair of (3, 3).

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

7 0
2 years ago
( PLEASE HELP ) <br><br> What is the solution to the inequality below?
Lunna [17]

Answer:

Step-by-step explanation:

You are to take the square root across the inequality sign to make it plus or minus 3 squared.

The answer will therefore be C

5 0
2 years ago
Given a point on a line and the equation of a parallel or perpendicular line, write the equation of the line in point-slope form
Arlecino [84]

Answer: y - 5 = 0(x - 1)

==================================================

Explanation:

Recall that point slope form in general is written as such

y - y1 = m(x - x1)

where,

m is the slope

(x1,y1) is the point the line goes through

The given equation y = 7 can be written as y = 0x+7. So we see that this line has a slope of m = 0

Plug m = 0 along with the given point (x1,y1) = (1,5) into the point slope equation and we get

y - y1 = m(x - x1)

y - 5 = 0(x - 1)

which is the final answer

note: the equation in bold can be rearranged and simplified to get y = 5; however your teacher seems to want the answer in point-slope form, so we leave it as such.

6 0
3 years ago
Can someone please help me with 10-16 it’s due tomorrow!!! Please
VMariaS [17]
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2

12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15)  V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
7 0
3 years ago
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