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Agata [3.3K]
3 years ago
14

Have you done any factoring with variables? Which property (Commutative, Distributive, or Associative) do you think is most invo

lved in factoring? Do you think a polynomial can be a factor of another polynomial? Answer in full sentences.
Mathematics
2 answers:
vazorg [7]3 years ago
7 0
Idk how im supposed to answer this or whatevs bu
yes i have done factoring with variables.
distrubutive is the most involved in factoring method as i can tell.
i dont think ive studied this before or i mightve forgoten but im sure a polynomial can be factored into another one.
and yea. hope this helped in sum way
ASHA 777 [7]3 years ago
3 0

⇒x²y³=x*x*y*y*y=x*y*x*y*y=y*x*y*x*y--Writing factors in another way

⇒xy²z²=x*y*y*z*z=y*x*z*y*z=z*x*y*x*y*z---Writing factors in another way.

⇒xy+xy²=xy(1+y)

⇒y²z²-yzx=yz(yz-x)

Here ,we have used law of indices first, then used Commutativity , Associativity and Distributivity to factor Polynomial.

1.\rightarrow x^{a+b}=x^a \times x^b\\\\2.\rightarrow x \times y=y \times x----\text{Commutative Property}\\\\3.\rightarrow x \times (y \times z)= (x \times y) \times z=(x \times z) \times y---\text{Associaitive Property}

⇒Distributive Property of Multiplication with respect to addition and Subtraction

  →a×(b+c)=a×b+a×c

 → a×(b-c)=a×b-a×c

⇒Yes, A polynomial can be factor of another polynomial.

For Example:

⇒ x²-a², has two factors equal to , (x+a) and (x-a), where , x²-a², is a quadratic polynomial and two of it's factors are ,(x+a) and (x-a) which is also a polynomial of degree 1.

 

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Of the entering class at a​ college, ​% attended public high​ school, ​% attended private high​ school, and ​% were home schoole
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Answer:

(a) The probability that the student made the​ Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})

Compute the probability that the student made the​ Dean's list as follows:

P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)

         =(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655

Thus, the probability that the student made the​ Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D)}

             =\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

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Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

P(C^{c}|D^{c})=1-P(C|D^{c})

               =1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

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