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Roman55 [17]
2 years ago
13

( a+ b) ( a- b) ( a square + 4 square )​

Mathematics
2 answers:
ale4655 [162]2 years ago
6 0

Answer:

\sf a^4 +16a^2 -b^2 a^2 -16b^2

Explanation:

\sf ( a+ b) ( a- b) ( a^2 + 4^2)

expand

\sf (a^2-ba+ba-b^2 ) ( a^2 + 16)

simplify

\sf (a^2-b^2 ) ( a^2 + 16)

expand

\sf a^4 +16a^2 -b^2 a^2 -16b^2

Flura [38]2 years ago
3 0

Solution:

<u>Note that:</u>

  • Given expression: (a + b)(a - b)(a² + 4²)

Formula: (a + b)(a - b) = a² - b²

<u>Simplify the expression using the formula.</u>

  • (a + b)(a - b)(a² + 4²)
  • => {(a + b)(a - b)}(a² + 4²)
  • => (a² - b²)(a² + 16)
  • => a⁴ + 16a² - a²b² - 16b²
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Graph the system of inequalities. y is greater than 3x-4 4y-x is less than or equal to 8
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Answer:

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Step-by-step explanation:

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3 years ago

zhuklara [117]

Step-by-step answer:

Given:

A triangle

Perimeter  = 60 cm

longest side = 4* shortest side (x)

Solution:

longest side = 4x

shortest side = x

third (intermediate side = 60 -x -4x = 60-5x

The triangle inequality specifies that the sum of the two shorter sides must be greater than the longest side to form a triangle.  Hence

x + y > 4x

x + 60-5x > 4x

60 - 4x > 4x

8x < 60

x < 60/8 = 7.5, or

x < 7.5

Therefore to form a triangle, x (shortest side) must be less than 7.5 cm.

Examine the options: both 7 and 5 are both less than 7.5 cm.

40, 30 and 25 all have a problem because the longest side (4 times longer) will exceed the perimeter of 60.

Now also examine cases where 4x is NOT the longest side, in which case we need

4x>=y

or

4x >= 60-5x

9x >=60

x >= 6.67

so x=5 will not qualify, because 4x will no longer be the longest side.

The only valid option is x=7 cm

The side lengths for x=7 and x=5 are, respectively,

(7, 25, 28)

5, 20, 35  (in which case, the longest side is no longer 4x=20, so eliminated)

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3 years ago
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