You know a1.
So find a2, a3, and so on until a7.
a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
Now that we’ve learned how to solve word problems involving the sum of consecutive integers, let’s narrow it down and this time, focus on word problems that only involve finding the sum of consecutive even integers.
But before we start delving into word problems, it’s important that we have a good understanding of what even integers, as well as consecutive even integers, are.
Even Integers
We know that even numbers are integers that can be divided exactly or evenly by 22. Thus, the general form of the even integer nn, is n = 2kn=2k, where kk is also an integer.
In other words, since even numbers are the multiples of 22, we can represent an even integer nn by 2k2k, where kk is also an integer. So if we have the even integers 1010 and 1616,
Answer: see below
<u>Step-by-step explanation:</u>
If the figures are similar, then their corresponding sides are proportional.
ABCD ~ WXYZ
Answer:
D. 19.5 Ft.
Step-by-step explanation:
Formula: B · H = A
Substitution: 3.25 · 2 = 6.5
6.5 · 3 ( 3 Windows ) = 19.5 Ft.
Answer:
x=60
Step-by-step explanation:
divid the numbers
multiply all terms by the same value to eliminate fraction denominator
simplify
