<span>3.00x10^8 meters.
If I'm reading this problem correctly, light is traveling at 9.45x10^15 meters per year and that there's 3.15x10^7 seconds per year. So you desire to know the speed of light in meters per second. This is mostly an exercise in handing scientific notion. So we need to divide the total distance that light traveled by the number of seconds. With scientific notation, you divide the significands and subtract the exponents to perform division. So
9.45 / 3.15 = 3 ; Dividing the significands
15 - 7 = 8 ; Subtracting the exponents.
So the answer is 3x10^8 meters per second.
Since our data has 3 significant figures, the result should also have 3 significant figures, so the final result is 3.00x10^8 meters.</span>
Answer:
1.) is 78 2.) is 4
Step-by-step explanation:
Answer:
$461
Step-by-step explanation:
First, find the cost with the daily charge of $29.
Multiply 14 by 29, since the car was rented for 14 days:
14(29)
= 406
Find the cost with the distance traveled. Since there is only a charge after the first 100 km, subtract 100 from 320.
320 - 100
= 220
Find the charge by multiplying this by 0.25:
220(0.25)
= 55
Add this to the daily charge:
55 + 406
= 461
So, the cost will be $461
<h3>
Answer: 8.2 (choice B)</h3>
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Explanation:
First we'll need the length of segment BD, which I'll call x for now. The similar triangles allow us to set up the proportion below to solve for x
AD/BD = BD/DC
13/x = x/4
13*4 = x^2
52 = x^2
x^2 = 52
x = sqrt(52)
Segment BD is exactly sqrt(52) units long.
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Now focus your attention on triangle BDC. We'll use the pythagorean theorem to find BC
(BD)^2 + (DC)^2 = (BC)^2
( sqrt(52) )^2 + ( 4 )^2 = ( m )^2
52 + 16 = m^2
68 = m^2
m^2 = 68
m = sqrt(68)
m = 8.2462 approximately
m = 8.2
