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xenn [34]
2 years ago
5

The cost of renting a car is $29.00 a day plus $0.25 for every kilometre after the first 100km. What is the cost of renting the

car for 14 days and 320km. (linear equtations)
Mathematics
1 answer:
ira [324]2 years ago
3 0

Answer:

$461

Step-by-step explanation:

First, find the cost with the daily charge of $29.

Multiply 14 by 29, since the car was rented for 14 days:

14(29)

= 406

Find the cost with the distance traveled. Since there is only a charge after the first 100 km, subtract 100 from 320.

320 - 100

= 220

Find the charge by multiplying this by 0.25:

220(0.25)

= 55

Add this to the daily charge:

55 + 406

= 461

So, the cost will be $461

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3 years ago
Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every
Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

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Answer:

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