The answer is b because the slope is rise over run it goes up 2 times and right 4 times which are both positive so the answer is 2/4 or 1/2
Answer:
y=6x-76
Step-by-step explanation:
the information given is really nice because in order to write a linear equation linear we need 4 information:
at least one coordinate pair satisfy the line(if slope wasn't given then we need at least two)
The rate of change (slope)
And lastly the initial value(y-int)
in this case:
x:11 y:-10 slope(m):6 b=?
so I plug to solve to b
-10=6(11)+b
clearly b is -76
put it back into y=mx+b form
our final answer is going to be
y=6x-76
Answer:
y ≈ 12.3
Step-by-step explanation:
Using the SOH CAH TOA identity to get the value of y as shown;
sin theta = opposite/hypotenuse
opposite = y
hypotenuse = 15cm
theta = 180-(35+90)
theta = 180-125
theta = 55 degrees
sin 55 = y/15
y = 15sin55
y = 12.287
y ≈ 12.3 (to the nearest tenth)
I assume you're needing to find
given those two functions you have.
![\begin{aligned}(f+g)(x) &= f(x) + g(x) \\[0.5em] &= (5x^3+5x^2-6x+3) + (x^3-4x^2+x-2)\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28f%2Bg%29%28x%29%20%26%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%5B0.5em%5D%20%26%3D%20%285x%5E3%2B5x%5E2-6x%2B3%29%20%2B%20%28x%5E3-4x%5E2%2Bx-2%29%5Cend%7Baligned%7D)
From there, you combine like terms:
![\begin{aligned}(f+g)(x) &= f(x) + g(x) \\[0.5em] &= (5x^3+5x^2-6x+3) + (x^3-4x^2+x-2) \\[0.5em] &= 6x^3+x^2-5x+1\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%28f%2Bg%29%28x%29%20%26%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%5B0.5em%5D%20%26%3D%20%285x%5E3%2B5x%5E2-6x%2B3%29%20%2B%20%28x%5E3-4x%5E2%2Bx-2%29%20%5C%5C%5B0.5em%5D%20%26%3D%206x%5E3%2Bx%5E2-5x%2B1%5Cend%7Baligned%7D)