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goldenfox [79]
3 years ago
5

Trigonometry help questions in attachment

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0
Use the law of sines....

sin51/x=sin90/67

x=(67sin51)/sin90

x=52.07

....

tan39=(h-1.8)/44

h-1.8=44tan39

h=44tan39+1.8

h=37.4 m

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A hotel has a pool in the shape of a rectangle. The pool is 8 m long, 3 m wide, and 2,000 cm deep. What is the volume of the poo
Maslowich
Ok, first you need to change the 2,000 cm into meters and then you just multiply all the sides.
4 0
3 years ago
Find the perimeter of the figure. *<br> 5.7 m<br> 6.2 m<br> 8.1 m
vichka [17]

Answer:

20

Step-by-step explanation:

When looking for the perimeter just add all the numbers together.

5 0
3 years ago
Read 2 more answers
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0
3 years ago
A newspaper’s cover page is 3/8 text, and photographs fill the rest. If 2/5 of the text is an article about endangered species,
jolli1 [7]

Answer:

\frac{3}{20}

Step-by-step explanation:

Let x be the cover page

We are given that a newspaper 's cover page is \frac{3}{8} text and photograph fill the rest.

We have to find that how much part of cover's page is the article about endangered species

Text =\frac{3}{8}x

Remaining part =x-\frac{3}{8} x

Remaining part =\frac{8x-3x}{8}=\frac{5}{8} x

Therefore, a newspaper;s cover page fill with  Photograph =\frac{5}{8}

If the article about endangered species=\frac{2}{5} of text

Therefore, the article about endangered species=\frac{2}{5}\times\frac{3x}{8}=\frac{3}{20}x

Hence,  the article about endangered species is \frac{3}{20}of the cover page.

7 0
3 years ago
Read 2 more answers
One glass of milk provides 305mg of calcium. Maggie drinks one glass of milk every morning. How many grams of calcium does Maggi
Komok [63]
She drinks 4.27 grams on calcium in 14 days at one glass of milk containing 14 mg per day
8 0
3 years ago
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