Answer:
The values of k will be:
Step-by-step explanation:
Let the expression of polynomial P be
Let the expression if the polynomial Q be
Plug in Q(x) = 0
0 = x+2
x = -2
As (x+2) is a factor of 3x²-4kx-4k²
substitute x = -2 in the the polynomial
3x²-4kx-4k² = 0
Write in the standard form ax²+bx+c = 0
Factor out common term -4
Factor k²-2k-3: (k+1)(k-3)
Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)
solving k+1=0
k+1 = 0
k = -1
solving k-3=0
k-3=0
k = 3
Thus, the values of k will be:
Answer:
The equation for the distance Jane's trainer bikes is 
.
Step-by-step explanation:
We have attached diagram for your reference.
Given:
Distance traveled on bike towards south = 16 miles
Distance she ran towards west = 12 miles
We need to find distance Jane's trainer bikes.
Solution:
Let the distance Jane's trainer bike be 'x'.
Now we will assume it to be right angled triangle.
So by Pythagoras theorem which states that;
"Square of the third side is equal to the sum of square of the other two sides."
framing in equation form we get;
Hence the equation for the distance Jane's trainer bikes is .
On solving we get;
Hence Jane's trainer bikes a distance of 20 miles.
