Answer:
Step-by-step explanation:
Given that a bag contains 40 cards numbered 1 through 40 that are either red or blue. A card is drawn at random and placed back in the bag.
This is done four times. Two red cards are drawn, numbered 31 and 19, and two blue cards are drawn, numbered 22 and 7.
From the above we cannot conclude that red cards and even numbers are mutually exclusive
Just drawing two red cards and because the two happen to be odd we cannot generalize the red cards have odd numbers.
This might have occurred due to simple chance from a comparatively large number of 40 cards.
Suppose say we have red cards 20, and 19 red 1 blue.
Then drawing 2 from 19 red cards have more probability and this can occur by chance.
So friend's conclusion is wrong.
As you can see, every time x increases by 2, y decreases by 5.
So, we have
Answer:
see explanation
Step-by-step explanation:
Given
f(x) = x² - 6x + 8 and g(x) = x + 2
To solve f(x) = g(x), equate the right sides, that is
x² - 6x + 8 = x + 2 ← subtract x + 2 from both sides
x² - 7x + 6 = 0 ← in standard form
(x - 1)(x - 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x - 6 = 0 ⇒ x = 6
These solutions can be verified from the tables, that is
f(x) = g(x) = 3 ← when x = 1
f(x) = g(x) = 8 ← when x = 6
Answer:
A) 
Step-by-step explanation:
Given:
A graph of a function.
When we analyze the given graph, it is of a <em>parabola</em>.
To find:
The interval of values of 
where the function is increasing.
Solution:
First of all, let us learn about the meaning of increasing and decreasing functions.
1. A function 
is known as increasing in an interval 
when
Value of y keeps on increasing when we move from the value of x from a to b.
2. A function is known as decreasing in an interval when
Value of y keeps on decreasing when we move from the value of x from a to b.
On analyzing the given graph , we can see that the graph is decreasing on the interval: 
and is increasing on the interval:
When we choose from the options,
The correct answer is option A)
