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Daniel [21]
4 years ago
12

Whats 1+11111111111111111111111

Mathematics
2 answers:
yan [13]4 years ago
3 0

Answer:

11111111111111111111112

Lubov Fominskaja [6]4 years ago
3 0

Answer:

24

Step-by-step explanation:

add the ones in the right side which I think is 23 and then add the 1 which it sound be 24

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Given cos(4x)+2<br><br> Find: Period, Shift, &amp; Range
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\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

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now, with that template in mind, let's see

\bf \begin{array}{llccll}&#10;cos(&4x&+0)&+2\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&B&C&D&#10;\end{array} &#10;\\\\\\&#10;period\qquad \cfrac{2\pi }{B}\implies \cfrac{2\pi }{4}\implies \cfrac{\pi }{2}&#10;\\\\\\&#10;\textit{horizontal/phase shift}\qquad \cfrac{C}{B}\implies \cfrac{0}{4}\implies 0\impliedby none&#10;\\\\\\&#10;\textit{vertical shift}\qquad D=+2\impliedby \textit{2 units up}

now the range, how far up and down it goes on the y-axis

well, for the graph of cos(x), the range is, goes up to 1, down to -1, is all,

the midline is at 0

now, with a vertical shift of 2 upwards, it moves the midline by 2 units, used to be at 0, now is at y = 2, but the amplitude never changed, is goes up and down still one unit,

but with the midline at 2, goes up to 3 and down to 1, so the range is 3 ⩽ y ⩽ 1
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4 years ago
Pls can any one help me with question two pls
kotegsom [21]

Answer:

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3 years ago
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Vadim26 [7]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

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\qquad \tt \dashrightarrow \:\tt6x {}^{4} −2x {}^{3}  +7x {}^{2} −x +  7x {}^{4} + 2x {}^{3} −5x + 7

Now, move all like terms aside :

\qquad \tt \dashrightarrow \:6 {x}^{4}  + 7 {}x^{4}  - 2 {x}^{3}  + 2 {x}^{3}  + 7 {x}^{2}  - x - 5x + 7

Add the like terms ~

\qquad \tt \dashrightarrow \:13 {}x^{4}   + 7 {x}^{2}   + 6x + 7

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Step-by-step explanation:

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3 years ago
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