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3 years ago

How much would 3 1/4 pound of hamburger cost at 699 per pound

Mathematics

1 answer:

Ratling [72]3 years ago

4 0

$2271.75 unless you meant $6.99 then that would be $22.75. Just multiply 3.25 by 699 or 6.99

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Tennis star Rafael Nadal lost at the Australian Open. How many Grand Slams has he won?

cluponka [151]

Answer:

Nadal won but it is the only major he hasn't won at least twice with 13 at Roland Harris four at the U.S

4 0

2 years ago

How much money should a student place in a time deposit in a bank that pays 1.1% compounded annually so that he will have Php 20

STatiana [176]

Let us say that:<span>
P = present value
F = future value
i = interest rate
n = period

P = F / [ (1 + i ) ^n ]
P = 200000 / [ (1 + 0.011) ^6 ]
P = 187293.65

<span>Therefore the student must put up Php 187,293.65</span></span>

5 0

3 years ago

Please help me there can only be one answer

12345 [234]

Answer:-
I think it’s the last option where x and y both are zero.
2x + 2y = 0
Here x = 0 and y = 0.
Hope it helps if u hv any questions feel free to ask...hv a grt day :)

4 0

3 years ago

What is the apr for a $585 tablet with 12 payments of $50.81

JulsSmile [24]

Answer:

the answer is 4%

Step-by-step explanation:

585/12=48.75

50.81-48.74=2.06

now 2.06 that's the money from interest rate

so now 2.06/50.81=0.04

so the answer is 4%

3 0

3 years ago

Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of

bearhunter [10]

Answer:

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

6 0

3 years ago