3 years ago

(3x-2)(2x^2+3x-1), after I distribute how would I get an exponent of three, for the 6x?

1 answer:

Aliun [14]3 years ago

7 0

Because when multiplying you add the number of variables, and there are 3 X's so it would be 6x with an exponent of 3

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maksim [4K]

43 to the nearest would be 40

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3 years ago

goldfiish [28.3K]

Pascal's triangle up to the 5th iteration is

$\begin{array}{cccccc}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\\1&5&10&10&5&1\end{array}$

This tells us

$(x-2)^5=\boxed{1}x^5(-2)^0+\boxed{5}x^4(-2)^1+\boxed{10}x^3(-2)^2+\boxed{10}x^2(-2)^3+\boxed{5}x^1(-2)^4+\boxed{1}x^0(-2)^5$

so the second term in the expansion is

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3 years ago

seraphim [82]

Answer:

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Step-by-step explanation:

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GalinKa [24]

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3 years ago

erastovalidia [21]

Answer:

10/3 liters

Step-by-step explanation:

Divide (4/3) by 2, then multiply by 5

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3 years ago