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3 years ago

14

Katelyn bought 3 packages of ground beef.The packages weighed 2.65 lbs,1.85 lbs,and 2.46 lbs.She divided the ground beef into 4

packages,each the same weight.How many pounds of ground beef were in each package?

1 answer:

NISA [10]3 years ago

5 0

Answer: 1.74lbs

Step-by-step explanation:

2.65 + 1.85 + 2.46 = 6.96

6.96/4 = 1.74

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A student started out poorly on his first mathematics test. However, he doubled his score on each of the next two tests. The thi

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His score is 50

How to:
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Add all three and divide by 3

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2 years ago

A sequence is defined recursively by the formula f(n+1) =f(n) + 3 the first term of the sequences is -4 what is the next term in

MArishka [77]

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3 years ago

Two parallel lines are crossed by a transversal. What is the value of h? h = 60 h = 80 h = 100 h = 120

lisabon 2012 [21]

I added the diagram of the question.

<u><em>Answer:</em></u>
h = 60°

<u><em>Explanation:</em></u>
We are given that lines k and l are parallel lines.
This means that angles 120° and h are <u>supplementary angles</u>.
This means that their measures <u>add up to 180°</u>

<u>Therefore:</u>
180° = 120° + h
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Hope this helps :)

8 0

3 years ago

Read 2 more answers

42 is 30% of what number??? Add work plz

romanna [79]

X - the number

$30\% x =42 \\
\frac{30}{100}x=42 \\
\frac{3}{10}x=42 \\
x=42 \times \frac{10}{3} \\
x=\frac{420}{3} \\
x=140$

42 is 30% of 140.

7 0

3 years ago

Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia

ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

Xa = Xb

-6 + (3*t) = 7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

(6.8*t) = 13.4

t = 13.4/6.8

t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0

2 years ago