Answer:
4/10
Step-by-step explanation:
there's 10 equal selections and there's 4 chances that the spinner will land on A. 4/10 = 0.4 on the probability scale
4/5 of the original amount at the start of the month will remain. The amount at the start of every month will change. Thus:
an = 4/5 (an-1) ; where a1 = 500.
<span>1st fold thickness : (2 x 0.0125) = 0.025
2nd fold : (2 x 0.025) = 0.05
3rd fold : (2 x 0.05) = 0.10
4th fold : (2 x 0.10) = 0.20
5th fold : (2 x 0.20) = 0.40
6th fold : (2 x 0.40) = 0.80</span>
Answer:
Step-by-step explanation:
Given
Sample Space = 10 to 99
First, we calculate the sample size (n)
Solving (a): P(32)
In 10 to 99, there is only 1 32.
So,
Solving (b): P(Odd)
There are 45 odd numbers between 10 and 99
i.e.
So:
Solving (c): P(Multiple of 5)
There are 18 multiples of 5 between 10 and 99
i.e
