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3 years ago

Area of the rhombus is 24cm sq. And its perimeter 20cm what is its height

Mathematics

1 answer:

-Dominant- [34]3 years ago

6 0

Answer:

h = 4.8 cm

Step-by-step explanation:

Area = 24cm²

Perimeter = 20 cm

Perimeter = 4 sides

20 = 4 × side

Side = 20/4

A side = 5 cm

Area of parralelograms = base × height

h = ?

24 = 5 × h

h = 24/5

h = 4.8 cm

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Is -40/8 positive or negative?

xeze [42]

Answer:

Negative. The answer gives - 5

6 0

3 years ago

Read 2 more answers

School is making digital backups of old reels of film in its library archives the table shown approximate run Times of the films

Gemiola [76]

One technique that you can apply when solving such a problem is trial and error. We try to use each equation to prove that a given value of x on the table given will correspond to the value of y on the table.

a) Let's try to put x = 3 for the first equation and we must get an answer equal to 2.25.

$y=7.72(3)-29.02=-5.86_{}$

Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

b) We put x = 3 on the second equation and solve for y

$y=-7.52(3)^2+0.19(3)+3.26=-63.85$

Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

c) We put x = 3 on the third equation and solve for y,

$y=0.4(3)^2+0.79(3)-4.93=1.04$

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

$y=0.4(5)^2+0.79(5)-4.93=9.02$

which has a slight deviation on the given value of y on the table for x = 5. let's try for x = 7. We have

$y=0.4(7)^2+0.79(7)-4.93=20.2$

and the answer has a small deviation compared to the actual value given. The other values of x can again be put on the equation and check their corresponding value of y, and the resulting values are as follows

$\begin{gathered} y=0.4(8)^2+0.79(8)-4.93=26.99 \\ y=0.4(12)^2+0.79(12)-4.93=62.15 \\ y=0.4(14)^2+0.79(14)-4.93=84.53 \end{gathered}$

And as you can see, the deviation of values from the table to calculated becomes smaller. Hence, this is the best model.

d) We put x = 3 on the third equation and solve for y,

$y=4.19(1.02)^3=4.45_{}_{}$

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

$y=4.19(1.02)^5=4.63$

where the answer's deviation is too large compared to the value of y if x = 5 on the table given.

Based on the calculations used above, the best equation that can be a good model is equation 3.

5 0

1 year ago

Prove that there is a positive integer that equals the sum of the positive integers not exceeding it. Is your proof constructive

Elena L [17]

Answer:

Constructive Proof

Step-by-step explanation:

Let x be a positive integer

x must be equal to sum of all positive integers exceeding it

i.e.

x = x + (x - 1) + ( x - 2) + ......... + 2 + 1

Equivalently,

x = ∑i (where i = 1 to x)

The property finite sum;

∑i (i = 1 to x) = x(x + 1)/2

So,

x = x(x + 1)/2 ------- Multiply both sides by 2

2 * x = 2 * x(x + 1)/2

2x = x(x + 1)

2x = x² + x ------- subtract 2x from both sides

2x - 2x = x² + x - 2x

0 = x² + x - 2x ----- Rearrange

x² + x - 2x = 0

x² - x = 0 ------ Factorise

x(x - 1) = 0

So,

x = 0 or x - 1 = 0

x = 0 or x = 1 + 0

x = 0 or x = 1

But x ≠ 0

So, x = 1

The statement is only true for x = 1

This makes sense because 1 is the only positive integer not exceeding 1

1 = 1

It is a Constructive Proof

A proof is constructive when we find an element for which the statement is true.

8 0

3 years ago

Angela is going on vacation to Mexico. She needs to buy new shirts for her trip. She buys 10 new shirts that cost her a total of

choli [55]

Angela bought 4 casual shirts, and 6 dressy shirts.

To find this, I used the equation ($18c) + ($25d) = $222, and filled in for c (casual) and d (dressy) until the outcomes were the same. Filling in for c and d, you'll get ($18 * 4) + ($25 * 6) = $222. Solving both sides, you'll get $72 + $150 = $222 or $222 = $222. Thus meaning she bought 4 casual shirts and 6 dressy shirts,

I hope this helps!

7 0

3 years ago

Pretty pretty please if ur good at geometry!! Help a girl out!!

sweet-ann [11.9K]

Answer:

Yes, They are similar by SSS PMK similar to LMQ.

Step-by-step explanation:

Similar triangles corresponding side lengths are in a proportion.

KM corresponds with MQ

PM corresponds with LM.

Set up this proportion.

$\frac{km}{pm} = \frac{lm}{mq}$

$\frac{15}{28} = \frac{21}{39.2}$

Cross multiply

$588 = 588$

So the triangles ARE Similar.

PM corresponds with LM
KM corresponds with MQ
PK corresponds with LQ
So PMK is similar to LMQ

4 0

3 years ago

Area of the rhombus is 24cm sq. And its perimeter 20cm what is its height​

Area of the rhombus is 24cm sq. And its perimeter 20cm what is its height