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zhannawk [14.2K]
3 years ago
6

21/4-(13/5+25/6÷25/8) remember this is a fraction problem the forward lashes are the separation of the numerator and the denomin

ator
Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

$10 \frac{14}{15} $

Step-by-step explanation:

Given :

$\frac{21}{4}-\left(\frac{13}{5}+\frac{\frac{25}{6}}{\frac{25}{8}} \right)$

$= \frac{21}{4}-\left(\frac{13}{5}+\frac{25}{6} \times \frac{8}{25} \right)$

$=\left( \frac{21}{4}-\frac{13}{5}\right)+\frac{4}{3} $

$=\left( \frac{105-52}{20}\right)+\frac{4}{3} $

$= \frac{53}{20}+\frac{4}{3} $

$= \frac{53}{5}+\frac{1}{3} $

$=\frac{159+5}{15}$

$=\frac{164}{15}$

$=10 \frac{14}{15} $

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Xin graphs the equation y =4x - 6.
Art [367]

Answer:

Both D and E are true statements.

Step-by-step explanation:

When you have the base form of slope-intercept form:

y = mx + b

The m (which is the coefficient of x) is the slope of the line. In this case that would be 4.

The b is the intercept. In this case it would be -6

8 0
3 years ago
How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
3 years ago
Anyone can u plsss help I now failing math and I need to get this right, I get to redo it so plsss anyone
vaieri [72.5K]

i think it is 487.5. i may be wrong tho. hope this helps!

3 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!! I don’t get it all :((((
asambeis [7]
The answer is 35 hope this helps
4 0
3 years ago
Select the cone(s) that are similar to a cone with a height of 9 meters and a radius of 3 meters.
choli [55]

Answer:

I think it is option 4, because it has the same scale.  The height is 3 times as much as the radius.

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4 years ago
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