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4 years ago

Write a digit (0-9) in the boxes below to make each comparison true

1 answer:

6 0

The digits (0–9) needed to make each comparison true are bolded and underlined
.402 < 412

230 > 160

605 = 605

93 < 281

460 > 450

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Y is inversely proportional to x, when Y = 7, x = 4.

babymother [125]

Answer:

The given statement Y = 7, x = 4 is False.

Step-by-step explanation:

We are given:

Y is inversely proportional to x, when Y = 7, x = 4.

We need to tell if the statement is True or False: the constant of proportionality, k, is 20.

Y is inversely proportional to x

We can write it as: $y\:\alpha \:\frac{1}{x}\\y=\frac{k}{x}$

Now, we need to check when Y=7, x = 4 is true or false

We are given k = 20

Now, I can find value of y, by putting values of k and x in the equation:

$y=\frac{k}{x}\\y=\frac{20}{4}\\y=5$

When we put x = 4, and k =20, we get Y=5 and not Y=7

So, The given statement Y = 7, x = 4 is False.

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3 years ago

Can everyone give me there nicest greet

SOVA2 [1]

Answer:

Hi how are you doing?. Is that nice enough

Step-by-step explanation:

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4 years ago

Does anyone else play woozworld? if so, add me SummerRae0

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Ok I will add u to if you can help me with my test

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3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 400 babies were born, a

Masja [62]

Answer:

(a) 99% confidence interval for the percentage of girls born is [0.804 , 0.896].

(b) Yes, the proportion of girls is significantly different from 0.50.

Step-by-step explanation:

We are given that a clinical trial tests a method designed to increase the probability of conceiving a girl.

In the study 400 babies were born, and 340 of them were girls.

(a) Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of girls born = $\frac{340}{400}$ = 0.85

n = sample of babies = 400

p = population percentage of girls born

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.85-2.58 \times {\sqrt{\frac{0.85(1-0.85)}{400} } }$ , $0.85+2.58 \times {\sqrt{\frac{0.85(1-0.85)}{400} } }$ ]

= [0.804 , 0.896]

Therefore, 99% confidence interval for the percentage of girls born is [0.804 , 0.896].

(b) Let p = population proportion of girls born.

So, Null Hypothesis, $H_0$ : p = 0.50 {means that the proportion of girls is equal to 0.50}

Alternate Hypothesis, $H_A$ : p $\neq$ 0.50 {means that the proportion of girls is significantly different from 0.50}

The test statistics that will be used here is One-sample z proportion test statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of girls born = $\frac{340}{400}$ = 0.85

n = sample of babies = 400

So, the test statistics = $\frac{0.85-0.50}{\sqrt{\frac{0.85(1-0.85)}{400} } }$

= 19.604

Now, at 0.01 significance level, the z table gives critical value of 2.3263 for right tailed test. Since our test statistics is way more than the critical value of z as 19.604 > 2.3263, so we have sufficient evidence to reject our null hypothesis due to which we reject our null hypothesis.

Therefore, we conclude that the proportion of girls is significantly different from 0.50.

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3 years ago

Find the interquartile range (IQR) of the data in the box plot below.

den301095 [7]

Answer:

IQR=0.2

Step-by-step explanation:

0.8-0.6=0.2

5 0

3 years ago

Read 2 more answers