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3 years ago

A day of the week is randomly chosen at random . What is the probability of choosing a Monday or Tuesday S?

Mathematics

1 answer:

attashe74 [19]3 years ago

6 0

Answer:

2 out of 7

Step-by-step explanation:

There are 7 days in a week( at least the last time I checked) Monday and Tuesday are 2 days of that week. Therefore it is 2/7.

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Which graph represents the solution set of the system of inequalities? {y<−3x−2y<br> y≤x−2

irina1246 [14]

Answer:

Option 1

Step-by-step explanation:

In each inequality we have the equation of a line.

The first step in solving this problem is to identify each line in the figures.

To do this, we willient your cut points.

y = x-2

We do y = 0

0 = x-2

x = 2. This line cuts the x-axis at x = 2.

Now we do x = 0

y = -2.

This line cuts the y-axis in y = -2.

Now we can identify this line in the figure.

The inequality is:

y≤x - 2

Then the region that represents this inequality are all the points below the line y = x-2 and also those that belong to the line.

Try for example the point (0, -4) that is below this line.

-4≤0-2

-4≤-2. The inequality is met.

We do the same for the other line:

y<-3x - 2

y = -3x-2.

The cut points are:

2 = -3x

x = -2 / 3

y = -2

Locate in the graphs the line that meets these characteristics.

The region understood by this inequality are all points below the line

y = -3x-2 and which, in turn, are below the line y = x-2.

Once again, the point (-4.0) complies with both inequalities.

Identify these characteristics in the options, and you will see that the correct option is the first

4 0

3 years ago

Read 2 more answers

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$