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irina1246 [14]
3 years ago
7

two rectangular properties share a common side. Lot is 33 feet wide and 42 feet long. The combined area of the lots is 1,848 squ

are feet .How many feet wide I Lot B​
Mathematics
1 answer:
klio [65]3 years ago
4 0

First, find the area of lot A.

To find the area, multiply the length by the width.

33*42=1,386

Now, subtract the area of lot a from the total area. This will give us the area of lot b.

1,848-1,386=462

The area of lot b is 462 square feet.

Finally, divide the area of lot b (462) by its length to find the width. Since they both share a side, we know that it’s length is 42 feet.

462/42=11

Lot b is 11 feet wide.

Hope this helps!

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------------------------------------------------------
Given information
------------------------------------------------------
100%  = $27.60

------------------------------------------------------
Rewriting it
------------------------------------------------------
\$27.60 = 100 \%
\$1 = 100 \div 27.60 \%
\$1 =  \frac{250}{69} \%

------------------------------------------------------
Find $4.14 in percentage
------------------------------------------------------
\$1 = \frac{250}{69} \%
\$4.14 =  \frac{250}{69}  \times 4.14
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Answer: 15%
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