Make a conditional relative frequency table for the columns of movie type. Determine which statement has the strongest associati
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First we calculate the z-score for this situation.
Finding <em>P</em>(x < 5.3) is the same as finding <em>P</em>(<em>z</em> < -0.8). Using a table of standard normal distribution and z-scores we see that the probability is 0.21186.
Finding <em>P</em>(x < 5.3) is the same as finding <em>P</em>(<em>z</em> < -0.8). Using a table of standard normal distribution and z-scores we see that the probability is 0.21186.