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ki77a [65]
3 years ago
7

20%3Dx%5E%7By%7D" id="TexFormula1" title="\frac{3^{\frac{1}{2} } }{8^{\frac{1}{2} } } =x^{y}" alt="\frac{3^{\frac{1}{2} } }{8^{\frac{1}{2} } } =x^{y}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
ehidna [41]3 years ago
7 0

Answer:

\frac{ {3}^{\frac{1}{2} } }{ {8}^{ \frac{1}{2} } }  =  {x}^{y}

{ (\frac{3}{8} )}^{ \frac{1}{2} }  =  {x}^{y}

x =  \frac{3}{8} and \:  \: y =  \frac{1}{2}

frosja888 [35]3 years ago
5 0

Answer:

\frac{3^{\frac{1}{2} } }{8^{\frac{1}{2} } } =x^{y} \\  \\   \bigg( \frac{3}{8} \bigg)^{ \frac{1}{2} }   =  {x}^{y}  \\  \\  \implies \:  x =  \frac{3}{8}  \:  \: and \:  \: y =  \frac{1}{2}  \\

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