Set up a proportional relationship:
xf/1n=(f/5)/(n/3)
xf/1n=3f/(5n) multiply both sides by 1n
xf=3f/5 so
x=3/5
Dave must mix in 3/5 of a cup of fruit with a single cup of nuts.
You could of also just noted that you need to multiply 1/5 times 3 because 1/5 mixes with just 1/3 of a cup of nuts...
Answer:
For question 3, you would just add 2 to the x values and subtract 2 from the y values, so it would be:
J' (-2, 5)
K' (2, 6)
L' (1, 2)
M' (-3, 1)
For question 4 you would subtract 7 from the x values and 6 from the y values, and that would be:
W' (-6, 1)
X' (-1, -1)
Y' (-3, -6)
Z' (-8, -4)
For question 9 you would end up with:
X' (6, -5)
Y' (7, 1)
Z' (4, 0)
For question 10 you would end up with:
Q' (-1, 2)
R' (1, 7)
S' (-2, 6)
T' (-4, 1)
For question 11 you would end up with:
L' (4, 1)
M' (8, 5)
N' (6, 7)
P' (2, 3)
For question 12 you would end up with:
G' (6, -7)
H' (6, -4)
I' (1, -7)
Hope this is what you were looking for!
Step-by-step explanation:
Answer:
69 <-- quotient
---
Step-by-step explanation:
8)555
48
--
75
72
--
3 <-- remainder
Answer:
D. x-intercept is -5 and the y-intercept is -2
Answer:
Rounding it to two decimal places, we get distance, 
Step-by-step explanation:
Given:
The two points are 
The distance between the two points can be obtained using the distance formula which is given as:
Here, for the points,
Therefore, the distance between the points is:
Rounding it to two decimal places, we get
