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NARA [144]
3 years ago
13

Priya has a recipe for banana bread. She uses 17 1/2 cups of flower to make 5 loaves of bread Andre will follow the same recipe.

He will make b loaves of bread using f cups of flour
Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer:

Step-by-step explanation:

5 loaves of bread requires 17 1 /2 cups of floor = 17.5 cups of flour

So, 1 loaf of bread requires = 17.5 / 5 = 3.5 cups of flour

So, b loaves of bread requires = 3.5 x b cups of flour

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8.4 gallons of gas for $23.94. Which equation can be used to determine the price of each gallon of gas?
mojhsa [17]
Here is the equation: (gas=g)

8.5g= 23.94

All you need to do is the inverse of multiplication on the other side. (division)

23.94/8.5= 2.81647.....

g= 2.82 (rounded to the hundredths place)

I hope this helps!
~kaikers
6 0
4 years ago
I need help w/ this!! thank you
Fittoniya [83]
<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
4 0
3 years ago
A University has 30,600 students think school counselor estimates that 2% of the students break three on my languages in a rando
xxTIMURxx [149]

Answer:

Counselor's estimate isn't correct.

Step-by-step explanation:

Total number of students in university = 30,600

2% break 3 of the languages

Therefore, 2/100 × 30600 = 612 students break 3 of the languages in the University according to the counselor.

In a random sample of 240 students, 20 break 3 of the languages.

% = 20/240 × 100 = 8.33%

SinceTotal number of students = 30,600

Therefore, 30,600/240 = 127.5

Which means 127.5 × 20 = 2550.

Which means 2550 students break 3 of the languages as against the 612 students stated by the counselor.

4 0
3 years ago
The graph of a quadratic function does not cross the x-axis, but crosses the y-axis in one place.
natulia [17]

Answer: D


Step-by-step explanation:

A quadratic function has a degree of 2 so there will be two roots.  The statement says the function does NOT CROSS THE X-AXIS so there are no real roots. That means both roots must be imaginary (complex).

5 0
3 years ago
A ball is released at a height of 8 inches to roll inside a half-cylinder it rolls to a height of 2 inches on the other side of
yuradex [85]

Answer:

C) 1/8 inch

Step-by-step explanation:

We are given the explicit formula

a_n=2(\frac{1}{4})^{n-1}, where n is the term number.

The third climb up would be the third term; this means we replace n with 3:

a_3=2(\frac{1}{4})^{3-1}\\\\a_3=2(\frac{1}{4})^2=2(\frac{1}{4}\times \frac{1}{4})=2(\frac{1}{16})=\frac{2}{16}=\frac{1}{8}

6 0
3 years ago
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