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3 years ago

Ron sees 3 dogs at the park. Hal sees twice as many dogs as Ron. How many dogs do they see in all?

Mathematics

1 answer:

Virty [35]3 years ago

8 0

Ron 3
Hal 2(3) =6

3+6 =9

they saw 9 dogs all together

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What is the value of y in this system of equations?

mote1985 [20]

Answer:

-21

Step-by-step explanation:

-6x + 2y = -18.........(i)

-3x - 2y = 54...........(ii)

add equ.(ii) to equ. (i)

(-6x + [-3x]) + (2y + [-2y]) = -18 + 54

-9x = 36

x = -4

sub x= -4 into equ (i)

-6(-4) +2y = -18

24 + 2y = -18

24 +18 = -2y

42 = -2y

y = -21

5 0

3 years ago

Read 2 more answers

Consider a home mortgage of $225,000 at a fixed APR of 4.5 % for 30 years. a. Calculate the monthly payment. b. Determine the

White raven [17]

<u>The formula for the monthly payment</u>.....

$M= \frac{P(1+r)^nr}{[(1+r)^n] -1}$ , where P = the principal amount, r = the monthly interest rate and n = the total number of months.

Here annual interest rate is given as 4.5%

So, the monthly interest rate $=\frac{4.5\%}{12}= 0.375\% = 0.00375$

Total number of months $= (30*12)months=360 months$

Also given that, the principal amount is $225000

a. So, the monthly payment will be.....

$M= \frac{P(1+r)^nr}{[(1+r)^n] -1}\\ \\ M= \frac{225000(1+0.00375)^3^6^0*0.00375}{(1+0.00375)^3^6^0 -1}\\ \\ M= \frac{225000(1.00375)^3^6^0*0.00375}{(1.00375)^3^6^0 -1} \\ \\ M \approx 1140$

Thus, the monthly payment will be approximately $1140

b. The <u>total amount paid</u> over the term of the loan will be: $\$ 1140*360 months = \$ 410400$

c. As the principal amount was $225000 , so the amount of interest $= (\$ 410400- \$ 225000)= \$ 185400$

So, the percentage of amount that is paid toward the principal $=\frac{225000}{410400}*100\% =54.82\%$

and the percentage of amount that is paid toward the interest $=\frac{185400}{410400}*100\%=45.18\%$

4 0

3 years ago

Sum of all natural numbers from100to300 which are divisible by 4and 5 is

My name is Ann [436]

If $x$ is a number that is both divisible by 4 and 5, then

$\begin{cases}x\equiv0\pmod4\\x\equiv0\pmod5\end{cases}$

4 and 5 are coprime, so we can use the Chinese remainder theorem to solve this system and find that $x=20n$ is a solution to the system, where $n$ is any integer. Simply put, any multiple of 20 fits the bill.

Now, there are 11 numbers between 100 and 300 that are divisible by 20 (100, 120, 140, and so on). We have $20n=100$ when $n=5$ , so the sum we want to compute is