Answer:
6c³
Step-by-step explanation:
18c³ = 2 × 3 × 3 × c × c × c
24c³ = 2 × 2 × 2 × 3 × c × c × c
Now we show the common factors in bold:
18c³ = 2 × 3 × 3 × c × c × c
24c³ = 2 × 2 × 2 × 3 × c × c × c
The common factor are:
2, 3, c, c, c
GCF = 2 × 3 × c × c × c = 6c³
Since he descended 12 meters, we subtract this from the overall height of Mount Ka'ala, so then we are only calculating how high ABOVE the sea level it is.
1232 - 12 = 1220
The height of Mount Ka'ala is therefore 1,220 meters.
To calculate how much a fifth of Mount Ka'ala is (since the ranger station is 2/5's up), we would divide this number by 5
1220 ÷ 5 = 244
Since ONE fifth of the height is 244 meters, TWO fifths would be double that amount.
244 x 2 = 488
488 meters.
The ranger station is 488m above sea level.
Rewriting the left-hand side as follows,
Answer:
2 x 7
Step-by-step explanation:
a * b = 14
2a + 2b = 18
(a * b)/b = 14/b Dividing both sides by b
a = 14/b
Substitute a in the perimeter equation
2(14/b) + 2b = 18
28/b + 2b = 18
2b - 18 + 28/b = 0
Multiply both sides by b
2b^2 - 18b + 28 = 0
Divide both sides by two
b^2 - 9b + 14 = 0
The Factors of 14 include -2 and -7 which add up to -9
(b - 2) * (b - 7) = 0
This has two answers because b can be either the side that is 2 long or 7 long, so there's no need to go back and solve for a.
2 x 7
