The correct answer is the last statement.
If the regulatory serine is mutated to alanine, then acetyl-CoA carboxylase will get activated spontaneously and will produce malonyl-CoA. The increased concentrations of malonyl-CoA will obstruct the oxidation of fatty acids by preventing the entry of fatty acids into the mitochondria.
It is because the AMP-activated protein kinase phosphorylates the serine residues of acetyl-CoA carboxylase to inactivate it. If a mutation occurs in such residues, then the AMPL cannot phosphorylate acetyl-CoA carboxylase and this enzyme will get activated spontaneously.
In such a situation, there will be more than sufficient production of malonyl-CoA, which will inhibit the admittance of more fatty acid getting inside the mitochondria; this will indirectly prevent the oxidation of fatty acids.
Homeostasis is the attempt to maintain stable conditions (particularly in an organism). It is done by using feedback loops (positive and negative).
Explanation:
It correctly reads;
A group of students use a device to study the energy transfer during the chemical reaction between pieces of eggshell (calcium carbon) and vinegar (acetic acid). During the experiment they use the same mass of eggshell but the concentration of the vinegar varies, (1%, 3% and 5%). Answer:
1. Explain why the energy transfer is not the same between the three tests of the experiment.
2. Describe how the device could be modified so that it can MORE ACCURATELY measure the energy transfer in each reaction.
