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AlexFokin [52]
3 years ago
7

HELP PLEASE!!! BEST ANSWER GETS BRAINLIEST

Mathematics
2 answers:
yarga [219]3 years ago
6 0
1/4 is the correct answer. 
Why?
The best way to figure this out is to take 12 from the first figure and compare it to 3 on the other figure because they're both the same side just different sizes.
3*4=12 so, 12*1/4=3

Hope this helps! (:
Mazyrski [523]3 years ago
5 0
The answer should be 1/4
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Somebody help with both questions
Minchanka [31]
1. X=5
2. I think I’m not sure is - 5.04
8 0
3 years ago
For circle O, mCD=125° and m
Burka [1]

CA is a diameter of the circle, so m\widehat{AC}=180^\circ, which means m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ. Then m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ.

This means m\angle CBO=55^\circ-35^\circ=20^\circ. Also, if m\angle AOB=55^\circ, then m\angle BOC=180^\circ-55^\circ=125^\circ, which in turns tells us that m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ.

3 0
3 years ago
Marvella writes the addition problem 5 + 6. Is this sum even or odd
Lemur [1.5K]
Your answer is going to be odd
6 0
3 years ago
Read 2 more answers
Simplify the expression. -2/3c -9/5 + 14c + 3/10
Andrew [12]

Answer:

13 \frac{1}{3} c - 1 \frac{1}{2}

Step-by-step explanation:

We want to combine alike terms so

-2/3c+14c & -9/5+3/10

14c-2/3

\frac{14}{1} c -  \frac{2}{3} c

Multiply 14/1 by 3/3 to get the denominators the same

\frac{42}{3} c -  \frac{2}{3} c

Subtract

\frac{40}{3} c

simplify

13 \frac{1}{3} c

now

\frac{3}{10}  -  \frac{9}{5}

Multiply 9/5 by 2/2

\frac{3}{10}  -  \frac{ 18}{10}

Subtract

- \frac{15}{10}

Simplify

- 1 \frac{1}{2}

put both together

13 \frac{1}{3}c  - 1 \frac{1}{2}

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

5 0
2 years ago
Read 2 more answers
How many 1-ft square tiles would it take to cover the room of a square room that is 27 ft on each side?
monitta

Answer:

729 tiles

Step-by-step explanation:

27 x 27 = 729

729 /1 =729

4 0
3 years ago
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