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aleksklad [387]
2 years ago
9

Compare 57^[2018] with 51^[2020]

Mathematics
2 answers:
Viktor [21]2 years ago
7 0

Answer:

Ilan lahat Ang kabuuang bilang ng mga nakalarawang bagay

olga2289 [7]2 years ago
7 0

Answer:

steps below

Step-by-step explanation:

I'm not sure if the question just want to compare which one is bigger or what...

log 57²⁰¹⁸ = 2018* log 57 = 3453.36

log 51²⁰²⁰ = 2020* log 51 = 3449.29

57²⁰¹⁸ > 51²⁰²⁰

If not correct, please REPORT it.

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SOooo .. I'm doing my Geometry DBA on edgenuity and i'm ready to quit.
Akimi4 [234]
No way don’t give up brotha
7 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
3 years ago
In this exercise, we are conducting many hypothesis tests to test a claim. Assume that the null hypothesis is true. If 400 tests
Brums [2.3K]

Answer:

Since the null hypothesis is true, finding the significance is a type I error.

The probability of the year I error = level of significance = 0.05.

so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5

Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.

3 0
3 years ago
What is the surface area of a sphere with a radius of 11 units
Otrada [13]

Answer: A≈1519.76³ Units

Step-by-step explanation:

A=4πr²

r = 11

11²=121

121 * 3.14 = 379.94

379.94(4) = 1519.76

A≈1519.76³ Units OR

A=4πr2=4·π·112≈1520.53084

4 0
3 years ago
Use the ratio table to solve the percent problem. What percent is 32 out of 80? 4% 32% 40% 80% ?.
attashe74 [19]

<u>The answer is 40%</u>

32 / 80 = 0.4000

.4000 * 100 = 40.00%

3 0
3 years ago
Read 2 more answers
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