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3 years ago

Find the distance between these points.

Mathematics

2 answers:

asambeis [7]3 years ago

8 0

Answer:

√85

Step-by-step explanation:

See image

Distance formula can be used to find the distance between two points.

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$

morpeh [17]3 years ago

6 0

Answer: Second option

$d=\sqrt{85}$

Step-by-step explanation:

The formula to find the distance between two points is:

$d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

In this problem the points are C(0, 4), T(-6, -3)

This is

$x_1=0\\\\x_2=-6\\\\y_1=4\\\\y_2=-3$

So the distance is:

$d=\sqrt{((-6)-0)^2 + ((-3)-4)^2}$

$d=\sqrt{(-6)^2 + (-7)^2}$

$d=\sqrt{36 + 49}$

$d=\sqrt{85}$

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Answer:

The maximum speed of Hal's airplane in still air is:

$v= 250\ miles/h$

The speed of the wind

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Step-by-step explanation:

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$v=\frac{d}{t}$ and $t*v=d$

The distance that Hal travels when traveling with the wind is:

$(2\ hours)(v + c) = 600$ miles

Where v is the speed of Hal and c is the wind speed.

The distance when traveling against the wind is:

$(3\ hours)(v-c) = 600$ miles

Now we solve the first equation for v

$(2)(v + c) = 600$

$2v + 2c = 600$

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Now we substitute the value of v in the second equation and solve for c

$3((300-c)-c) = 600$

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$900-6c = 600$

$-6c = 600-900$

$-6c = -300$

$6c = 300$

$c = 50\ miles/h$

Then:

$v= 300-(50)$

$v= 250\ miles/h$

The maximum speed of Hal's airplane in still air is:

$v= 250\ miles/h$

The speed of the wind

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