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4 years ago

Find the distance between these points.

Mathematics

2 answers:

asambeis [7]4 years ago

8 0

Answer:

√85

Step-by-step explanation:

See image

Distance formula can be used to find the distance between two points.

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }$

morpeh [17]4 years ago

6 0

Answer: Second option

$d=\sqrt{85}$

Step-by-step explanation:

The formula to find the distance between two points is:

$d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

In this problem the points are C(0, 4), T(-6, -3)

This is

$x_1=0\\\\x_2=-6\\\\y_1=4\\\\y_2=-3$

So the distance is:

$d=\sqrt{((-6)-0)^2 + ((-3)-4)^2}$

$d=\sqrt{(-6)^2 + (-7)^2}$

$d=\sqrt{36 + 49}$

$d=\sqrt{85}$

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Find the distance from the bank to the park. Leave your answer in simplest radical form if necessary.

ArbitrLikvidat [17]

We need to find the distance between (3, 10) and (10, 11), which is √(11-10)²+(10-3)² = √1+49 = √50 = 5√2
The distance between the bank and the park is D. 5√2.
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Hope this helps!

3 0

3 years ago

Read 2 more answers

Please Help! 30 POINTS! Given the following three points, find by hand the quadratic function they represent. (−1,−8), (0,−1),(1

ycow [4]

Answer:

(1) B

(2) D

Step-by-step explanation:

(1)

Let the quadratic function be:

$y = ax^{2} + bx + c$

For the point, (0,-1),

$y = ax^{2} + bx + c$

$-1=(a\times0)+(b\times0}+c\\-1=c\\c=-1$

Then the equation is:

$y = ax^{2} + bx -1$

For the point (-1, -8) ,

$y = ax^{2} + bx -1$

$-8=(a\times (-1)^{2})+(b\times -1)-1\\-8=a-b-1\\a-b=-7...(i)$

For the point (1, 2) ,

$y = ax^{2} + bx -1$

$2=(a\times (1)^{2})+(b\times 1)-1\\2=a+b-1\\a+b=3...(ii)$

Add the two equations and solve for a as follows:

$a-b=-7\\a+b=3\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\2a = -4\\a = -2$

Substitute a = -2 in (i) and solve for b as follows:

$a-b=-7\\-2-b=-7\\b=5$

Thus, the quadratic function is:

$f(x)=-2x^{2}+5x-1$

The correct option is (b).

(2)

The ordered pairs are:

(5, 7), (7, 11), (9, 14), (11, 18)

Represent them in an XY table as follows:

X : 5 | 7 | 9 | 11

Y : 7 | 11 | 14 | 18

Compute the difference between the Y values as follows:

Diff = 11 - 7 = 4

Diff = 14 - 11 = 3

Diff = 18 - 14 = 4

Now compute the difference between the Diff values:

d = 3 - 4 = -1

d = 4 - 3 = 1

Since the differences between the differences of the y-values is not consistent, the ordered pairs do not represent a quadratic equation.

The correct option is D.

8 0

3 years ago

6x^2+7x+2=0 find the solution

Masteriza [31]

6x^2+7x+2=0
(3x+2)(2x+1)=0
3x+2 = 0; x = -2/3
2x+1 = 0; x = -1/2

answer
x = -1/2 and x = -2/3

5 0

4 years ago

Read 2 more answers

PLEASE HELPPPPPPPP To get brainiest

jeka94

Answer:

Step-by-step explanation:

7 0

3 years ago

Please please please help!! i’ll mark the brainliest and give 15 points!!!!

Korolek [52]

9514 1404 393

Answer:

-108

Step-by-step explanation:

About the easiest way to do this for small values of n is to compute each of the terms using the given recurrence relation.

$a_1=4\\\\a_2=-3a_1=-3(4)=-12\\\\a_3=-3a_2=-3(-12)=36\\\\a_4=-3a_3=-3(36)=-108\\\\\boxed{a_4=-108}$

_____

Alternate solution

You recognize that the recurrence relation describes a geometric sequence with a first term of 4 and a common ratio of -3. The n-th term of a geometric sequence is ...

$a_n=a_1\cdot r^{n-1} \qquad\text{for first term $a_1$ and common ratio $r$}$

Then the 4th term will be ...

$a_4=4\cdot(-3)^{4-1}=4\cdot(-27)=-108$

3 0

3 years ago