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irina1246 [14]
3 years ago
8

Find the distance between these points.

Mathematics
2 answers:
asambeis [7]3 years ago
8 0

Answer:

√85

Step-by-step explanation:

See image

Distance formula can be used to find the distance between two points.

d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}  }

morpeh [17]3 years ago
6 0

Answer: Second option

d=\sqrt{85}

Step-by-step explanation:

The formula to find the distance between two points is:

d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}

In this problem the points are C(0, 4), T(-6, -3)

This is

x_1=0\\\\x_2=-6\\\\y_1=4\\\\y_2=-3

So the distance is:

d=\sqrt{((-6)-0)^2 + ((-3)-4)^2}

d=\sqrt{(-6)^2 + (-7)^2}

d=\sqrt{36 + 49}

d=\sqrt{85}

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Answer:

The maximum speed of Hal's airplane in still air is:

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The speed of the wind

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Step-by-step explanation:

Remember that the velocity v equals the distance d between time t.

v=\frac{d}{t}  and t*v=d

The distance that Hal travels when traveling with the wind is:

(2\ hours)(v + c) = 600 miles

Where v is the speed of Hal and c is the wind speed.

The distance when traveling against the wind is:

(3\ hours)(v-c) = 600 miles

Now we solve the first equation for v

(2)(v + c) = 600

2v + 2c = 600

2v= 600-2c

v= 300-c

Now we substitute the value of v in the second equation and solve for c

3((300-c)-c) = 600

3(300-2c) = 600

900-6c = 600

-6c = 600-900

-6c = -300

6c = 300

c = 50\ miles/h

Then:

v= 300-(50)

v= 250\ miles/h

The maximum speed of Hal's airplane in still air is:

v= 250\ miles/h

The speed of the wind

c = 50\ miles/h

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