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Anna007 [38]
2 years ago
9

Vehicle A has a 22-gallon fuel tank and averages 20 miles per gallon. Vehicle B has a 16.7-gallon fuel tank and averages 30 mile

s per gallon. Both vehicles have just begun traveling with full tanks. In how many miles will both vehicles have the same amount of fuel in their tanks?​
Mathematics
1 answer:
grin007 [14]2 years ago
7 0

Both vehicles will never have the same amount of fuel in their tanks

<h3>In how many miles will both vehicles have the same amount of fuel in their tanks?​</h3>

The given parameters are:

Vehicle A

Initial = 22-gallon

Rate = 20 miles per gallon

Vehicle B

Initial = 16.7-gallon

Rate = 30 miles per gallon

The equation of each vehicle is represented as;

Fuel = Initial - Rate * Number of miles

So, we have

y = 22 - 20x --- A

y = 16.7 - 30x --- B

Substitute y = 16.7 - 30x in y = 22 - 20x

16.7 - 30x = 22 - 20x

Collect the like terms

30x - 20x = 16.7 - 22

Evaluate the difference

10x = -5.3

Divide by 10

x = -0.53

Distance cannot be negative

Hence, both vehicles will never have the same amount of fuel in their tanks

Read more about linear equations at:

brainly.com/question/2226590

#SPJ1

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DanielleElmas [232]
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Pleas help me find the answer and show the work to this question
lions [1.4K]

Answer:

Leg\ 1 = 8

Leg\ 2 = 15

Step-by-step explanation:

Given: See Attachment

Required

Determine the length of the legs

To do this, we apply Pythagoras theorem.

Hyp^2 = Adj^2 + Opp^2

In this case:

17^2 = x^2 + (2x- 1)^2

Open Bracket

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Collect Like Terms

5x^2 - 4x + 1 - 289 = 0

5x^2 - 4x - 288 = 0

Solving using quadratic formula:

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So:

x = 8 or x = -7.2

Since, x can't be negative, then:

x = 8

One of the leg is:

Leg\ 1 = x

Leg\ 1 = 8

Leg\ 2 = 2x - 1

Leg\ 2 = 2*8 - 1

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Answer:

Vertex - (2,1)

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