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2 years ago

13

I really need help with this problem!!! Can someone help!!!! Please!!!

1 answer:

Alex_Xolod [135]2 years ago

5 0

9514 1404 393

Answer:

(a) 31.5 in²

Step-by-step explanation:

The area of a rhombus is half the product of the lengths of the diagonals.

A = 1/2(d1)(d2)

A = (1/2)(7 in)(9 in) = 31.5 in²

There are 31.5 in² of space in the rhombus for engraving.

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Arrange the digits 4, 6, 9, 2, 3 in the dividend and the digits 2, 5,2 in the divisor to give the greatest possible quotient.

Leviafan [203]

To get the greatest possible quotient, you need the biggest possible
dividend and the smallest possible divisor.

96,432 divided by 225 = 428.5666... <== greatest possible

23,469 divided by 522 = 44.9597... <== smallest possible

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2 years ago

A flashlight is projecting a triangle onto a wall, as shown below.

zavuch27 [327]

Answer:

Hence the correct option is 3rd option. 40

Step-by-step explanation:

If two figures are similar, then the ratio of the corresponding sides is proportional.

$\frac{15}{30} =\frac{20}{n} \\\\n=\frac{30 \times 20}{15} \\\\n= 40.$

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2 years ago

...................................................

snow_lady [41]

Answer:

3x + 2 = 59

Step-by-step explanation:

because the total is 59 so is definetly =59

and no of oranges in bag so there are 3 bags it means its 3x so the equation is 3x + 2 = 59

Hope it will help you

Lots of love from nepal <3 :)

5 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

Bryce left a 20% tip on a $45 dinner bill. What was<br> Bryce's total dinner cost?

marin [14]

Answer:

Answer below hopes it helps

Step-by-step explanation:

8 0

2 years ago