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hodyreva [135]
3 years ago
9

3x+17<47 -6x+9<25 Solve the inequalities and make a number line

Mathematics
1 answer:
k0ka [10]3 years ago
6 0

Answer: Read below.

Step-by-step explanation:

3x+17

Let's take the first one.

3x+17

Subtract 17

3x

Divide by 3

x

---------------------------------------------------------------------------------------------

Now the second one.

-6x+9

Here's the trick. You need to divide by -6; however, there's a rule. When you multiply or divide by negative numbers, the inequality sign flips.

x>\frac{16}{-6}

x>-\frac{8}{3}

---------------------------------------------------------------------------------------------

x has to be less than 10

x has to be greater than -\frac{8}{3} or -2.66 approximately.

in the number line, make a hollow circle on -\frac{8}{3} and draw an arrow up to 10 where, again, you have to make a hollow circle. The circles have to be hollow because neither -\frac{8}{3} nor 10 are part of the answers.

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) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
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Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

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Let X = Number of getting ones.

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Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

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Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

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4 years ago
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