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3 years ago

List the independent and dependent variable in the given relationship.

2 answers:

7 0

The independent variable is the money earned because John will earn $10 for each lawn he mows. This is true if he mows 1 lawn or 20 lawns; he will earn $10 per lawn. The dependent variable is the number of lawns. That is not a given. How much he will earn depends on the number of lawns mowed.

So the answer is the first one above. The independent variable is the money earned. The dependent variable is the number of lawns mowed.

This would also be true in other situations. For example, if a candy bar costs $1.50. The independent variable is $1.50. That price is that price per candy bar regardless of whether you buy 1 or 10. The dependent variable is the number of candy bars purchased. How much your overall total is depends on the number purchased.

Hope this helped!! :)

kaheart [24]3 years ago

4 0

The independent variable is your input (x-value) and the dependent variable (y-value) depends on what the input is.

y = 10x

y is total money earned
x = number of lawns mowed

The first answer listed

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lina2011 [118]

Step-by-step explanation:

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3 years ago

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3 years ago

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The unshaded area inside the figure to the right is 648 in.² Use this fact to write an equation involving x. Then solve the equa

FrozenT [24]

The second order polynomial that involves the variable x (border inside the rectangle) and associated to the unshaded area is x² - 62 · x + 232 = 0.

<h3>How to derive an expression for the area of an unshaded region of a rectangle</h3>

The area of a rectangle (A), in square inches, is equal to the product of its width (w), in inches, and its height (h), in inches. According to the figure, we have two proportional rectangles and we need to derive an expression that describes the value of the unshaded area.

If we know that A = 648 in², w = 22 - x and h = 40 - x, then the expression is derived below:

A = w · h

(22 - x) · (40 - x) = 648

40 · (22 - x) - x · (22 - x) = 648

880 - 40 · x - 22 · x + x² = 648

x² - 62 · x + 232 = 0

The second order polynomial that involves the variable x (border inside the rectangle) and associated to the unshaded area is x² - 62 · x + 232 = 0. $\blacksquare$

To learn more on polynomials, we kindly invite to check this verified question: brainly.com/question/11536910

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2 years ago

Complete the ordered pairs of two points on a line with a greater rate of change than the given linear function

elixir [45]

It would be (0,-3) and (2,3). You can see that they have a bigger distance compared to the other points being compared.

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3 years ago

Find the average value of f(x)=2x^5 over the interval [1, 5].

Ulleksa [173]

Answer:

: let's recall that the average value of a function for an interval of (a,b) is given by formula: k=1b−a∫baf(x)dx where; k:average value k=16−2∫62(x2−2x+5)dx k=14(∣∣∣x33−2x22+5x∣∣∣62) k=14(∣∣∣x33−x2+5x∣∣∣62) k=14[(633−62+5⋅6)−(233−22+5⋅2)] k=14[(2163−36+30)−(83−4+10)] k=14[(2163−6)−(83+6)] k=14[216−183−8+183] k=14[1983−263] k=14[1723] k=17212

QuestionThe average of a function over an interval is computed as (1/width of interval) times the definite integral of the function evaluated over the interval. The indefinite integral of e^2x is (1/2)e^2x. So the answer is found by evaluating:(1/2)*[(1/2)[e^8 - e^4]], or (1/4)[e^8 - e^4]which equals about 731.6.

Brainly.com

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Find the average value of f(x)=2/x over the interval [1, 3].

Answer · 0 votes

$\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll}average~rate\of~change\end{array}\\-------------------------------\\f(x)= \cfrac{2}{x} \qquad \begin{cases}x_1=1\x_2=3\end{cases}\implies \cfrac{f(3)-f(1)}{3-1}\implies \cfrac{\quad \frac{2}{3}-\frac{2}{1}\quad }{2}\\\\cfrac{\quad \frac{2-6}{3}\quad }{2}\implies \cfrac{\quad \frac{-4}{3}\quad }{\frac{2}{1}}\implies \cfrac{-4}{3}\cdot \cfrac{1}{2}\implies -\cfrac{2}{3}$

Wyzant

Question

Find the average value of the function f(x)=x^3 over the interval [0,2] and find the value(s) of x at which the function assumes the average values

Answer · 0 votes

The average value of f is defined as: 1/(b-a)∫ f(x) dx (where integral is evaluated from a to b) If we are to integrate f(x) = x3 we get: (1/4)* (x4) Applying formula for average value: [1/(b-a)]*[(1/4)*(x4)]a to b Evaluating this result where a = 0 and b = 2: [1/(2-0)]*[(1/4)*(x4)]a to b =(1/2)*[((1/4)*x4)]a to b =(1/2)*[((1/4)*(2)4) - (2*(0^4))] =(1/2)*[((1/4)*16)-0] =(1/2)*(4) =2

The average rate of change over the interval [a,b], or the secant line between the points a and b on the function f(x), is [f(a) - f(b)]/[a-b]. So, substitute a for 1 and b for 5, and you get [f(1) - f(5)]/[1–5]. The quotient of that is your average rate of change.

the average value of f(x) on [a,b] is ∫[a,b] f(x) dx ----------------------- b-a f' = 3x^2-6x f = x^3-3x^2+4 so, you want ∫[-1,3] x^3-3x^2+4 dx -------------------------- 3 - (-1) which I'm sure you can do.

1/2 e 2 - 1/2 or 3.19 Given: f(x)=2x 2 e 2x [0, 1] The average value of a function is: Where: a and b -intervals [a,b] f(x) - given function Substitute the values to the formula: In the integration of the function, we will use integration by parts: Let: u = 2x 2 dv = e 2x dx For du, get the derivative of u: du = 2(2x 2-1 ) = 4x dx For v, integrate dv: v = 1/2 e 2x Substitute the values to the integration by parts formula, and plug it in the solution: Get the integration by parts of xe 2x dx and let: u = x dv = e 2x dx for du,get the derivative of x du = dx For v, integrate dv v = 1/2 e 2x Substitute the values to the integration by parts formula, and plug it in the solution: Final answer: The average value of the function is 1/2 e 2 - 1/2 or 3.19

Step-by-step explanation:

plz brian list Oh and the real answer is k=17212

6 0

3 years ago