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swat32
2 years ago
6

Simplify. -14x^3/ x^3-5x^4 A) -14/5x-1; where x is not equal to 1/5,0 B) -14x/1-5x; where x is not equal to 1/5 C) 1-5x/-14x; wh

ere x is not equal to 0 D) -14/1-5x; where x is not equal to 1/5, 0
Mathematics
1 answer:
Karolina [17]2 years ago
3 0
It's D.  Factor x^3 out of the denominator leaving  1 - 5x, then cancel out the x^3 in the numerator with the one you factored out of the denominator.  That leaves you with 1 - 5x cannot equal 0.  Solve that for x and you get 1/5.  However, since we are talking vertical asymptotes and the x^3 is a removable discontinuity, we have to count it as a "problem".  Therefore, the other value of x that is not allowed is x = 0.
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2 years ago
What is the slope of the line that contains the points (4, -1) and (-1, 4)?
bija089 [108]

Answer:

slope = - 1

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (4, - 1) and (x₂, y₂ ) = (- 1, 4)

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2 years ago
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5 0
3 years ago
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8 6/7 =<br><br> i want it in fraction form and in the smallest form.
Ilia_Sergeevich [38]
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3 0
3 years ago
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In triangle ABC, angle bisectors line AD, line BE, and line CF meet at I. If DI = 3, BD = 4, and BI = 5, then compute the area o
Nikitich [7]

The area of triangle ABC is the amount of space on the triangle

The area of the triangle is 54.84 square units

<h3>How to determine the area of triangle ABC</h3>

Start by drawing the triangle (see attachment)

Next, calculate the measure of angle B using the following tangent ratio

\tan(B/2) = \frac 34

This gives

\tan(B/2) = 0.75

Take the arc tan of both sides

B/2 = 36.87

Multiply by 2

B = 73.74

Next, calculate the length of side AD using the following equation

AD = \tan(B) * BD

This gives

AD = \tan(73.74) * 4

AD =13.71

The area of the triangle is then calculated as:

Area = AD * BD

This gives

Area = 13.71 * 4

Area = 54.84

Hence, the area of the triangle is 54.84 square units

Read more about areas at:

brainly.com/question/24487155

8 0
2 years ago
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