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swat32
3 years ago
6

Simplify. -14x^3/ x^3-5x^4 A) -14/5x-1; where x is not equal to 1/5,0 B) -14x/1-5x; where x is not equal to 1/5 C) 1-5x/-14x; wh

ere x is not equal to 0 D) -14/1-5x; where x is not equal to 1/5, 0
Mathematics
1 answer:
Karolina [17]3 years ago
3 0
It's D.  Factor x^3 out of the denominator leaving  1 - 5x, then cancel out the x^3 in the numerator with the one you factored out of the denominator.  That leaves you with 1 - 5x cannot equal 0.  Solve that for x and you get 1/5.  However, since we are talking vertical asymptotes and the x^3 is a removable discontinuity, we have to count it as a "problem".  Therefore, the other value of x that is not allowed is x = 0.
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What is the inverse of the function f(x) = x - 12?
ludmilkaskok [199]

Answer: \displaystyle f(x)^{-1}=x+12

Step-by-step explanation:

     First, we will rewrite the function in terms of <em>y</em> as in y = x - 12.

     Second, we will swap the x and y values.

y = x - 12

x = y - 12

     Third, we will solve for y. In other words, we will isolate the <em>y</em> variable and get it "by itself" on one side of the equal sign.

x = y - 12

x + 12 = y

y = x + 12

      Lastly, we will change y back into terms of the function, but the inverse.

\displaystyle f(x)^{-1}=x+12

<em>Learn more about the </em><em>inverse of a function</em><em> here:</em>

<em>brainly.com/question/940569</em>

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Step-by-step explanation:

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