So, x = 13, x = √3 and x =7i.
now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value "a", that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.
now.... keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 - 7i, which is the other root.
Answer:
Below.
Step-by-step explanation:
Triangles ABC and CDE are congruent by 2 angles and the corrrespnding side (AAS).
Therefore AC = CE.
So C is the midpoint of AE.
Answer:
53°
Step-by-step explanation:
i will use ∩ to represent arc since there is no arc sign
if ∩EF = 34, then ∡EFC = 34
think of EFC as an angle in the larger circle
since EFC = 34, ABC = 34 because they are opposite angles and opposite angles are always congruent.
ABD = AB + BD = 19 + 34 = 53
