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Alex17521 [72]
3 years ago
6

What is the slope of the line represented by the equation y = –1/2x + 1/4 ?

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0
A)-1/2 is the slope. what ever is next to x is the slope
Vedmedyk [2.9K]3 years ago
5 0

slope = m

 slope equation = y=mx+b so the first number is the slope

-1/2

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Pls answer these questions correctly for brainly
FinnZ [79.3K]

40 - 3k + 10k = -10 - 8k - 10

40 + 7k = -10 - 8k - 10

40 + 7k = -8k - 20

40 + 7k - 40 = -8k - 20 - 40

7k = -8k - 60

7k + 8k = -8k - 60 + 8k

15k = -60

15k/15 = -60/15

k = -4

8 0
3 years ago
2ND QUESTION. PLEASE PLEASE HELP. 20 POINTS!!!!!!!!ANSWER IN FUL SENTENCES
kupik [55]

Answer:

i dont know what it means but the right image is 4 times larger than the left image

Step-by-step explanation:

6 0
2 years ago
If one supplementary angle measure 51 degrees the other angle measures 39 degrees?
mojhsa [17]
The answer to your question is false
7 0
3 years ago
The total amount of money saved in
fiasKO [112]
Answer is 14

Step by step explanation

The amount is same so
64+8w=92+6w
2w=92-64=28
w=14 => after 14 weeks
6 0
3 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
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