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Triss [41]
3 years ago
13

Use the rules for logarithms and exponents to write this equation in logarithmic form.?

Mathematics
1 answer:
Papessa [141]3 years ago
7 0

Answer:

ln K = ln (A) -\frac{\Delta H}{RT}

Step-by-step explanation:

For this case we have the following expression:

K = A e^{-\frac{\Delta H}{RT}}   (1)

And we want to find the value of ln K. If we apply natural log on both sides of the equation (1) we got:

ln K = ln(A e^{-\frac{\Delta H}{RT}})

Using the following property:

ln(xy) = ln (x) + ln(y) for x and y real numbers, x>0, y>0, then we have:

ln K = ln (A) + ln (e^{-\frac{\Delta H}{RT}})

Now since the natural log and the exponentiation are inverse operations we have this:

ln K = ln (A) + (-\frac{\Delta H}{RT})

And then the final expression for ln K is :

ln K = ln (A) -\frac{\Delta H}{RT}

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charle [14.2K]

Hello :D

$40.00 x 3 = $120.00

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5 0
3 years ago
What is the value of x? <br>A.39<br>B.41<br>C.26<br>D.17​
mojhsa [17]

Answer:

The answer is B.

Step-by-step explanation:

You have to use Pythogorean Theorem, c² = a² + b² where c is the hypotenuse and a,b is the side lengths :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Let a = 40,

Let b = 9,

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{c}^{2}  = 1600 + 81

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c =  \sqrt{1681}

c = 41 \: units

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3 0
3 years ago
Solve for x in the diagram below
ella [17]

Answer:

20

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago
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Lesechka [4]
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4 0
3 years ago
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