In the first slot lets calculate the chance of getting a w: 1/5
In the second slot calculate the chance of getting a o: 1/4 (notice how it's 4 not 5 because you already have one letter in the first slot so you have 4 left to choose from.)
In third slot, chance of getting a r: 1/3
In fourth slot, chance of getting a l: 1/2
In the fifth slot, if you got all the first four letters right, than you would be left with one letter, so your chances are 1/1 (100%) for the fifth slot
To calculate probability multiply all the fractions we got above: 1/5 x 1/4 x 1/3 x 1/2 x 1/1
We will then get: 1/(5x4x3x2x1) = 1/120
1/120 is the probability of the 5 slots showing the word "world"
Answer:
37.8÷7.6=4.974
It would be 4 complete cotton swabs High.
Answer:
<h2><em><u>
First box and last box.</u></em></h2>
Step-by-step explanation:
<h2><em><u>
It is the first box.</u></em></h2>
Distribute 7 to the first number
7 * -3/4 = -21/4
-21/4 = 5 -1/4
Distribute 7 to the second number
7 * -3
= -21
Put the numbers together
<h2><em><u>
5 -1/4x -21 is the answer.</u></em></h2>
<h2><em><u>
It is also the last box.</u></em></h2>
They separated the parenthesis.
So it is still 7 * -3/4
and
7*-3.
Hope this helps,
Kavitha
Answer:
The Answer is C.
Step-by-step explanation:
It is moved 2 spaces and is flipped from q1 to q4.
Answer: There is probability of 96.4% that a day in March will be foggy if it is a cloudy.
Step-by-step explanation:
Since we have given that
Probability of the days in March are cloudy = 57%
Probability of the cloudy days in March are foggy = 55%
Let A be the event of cloudy days in March.
Let B be the event of foggy days in March.
So, here,
P(A) = 0.57
P(A∩B) = 0.55
We need to find the probability that days are foggy given that it is cloudy.
We would use "Conditional probability":
Hence, There is probability of 96.4% that a day in March will be foggy if it is a cloudy.