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2 years ago

Please help me so I can pass this test

Mathematics

2 answers:

natka813 [3]2 years ago

7 0

Decimal place = 10.08

Whitepunk [10]2 years ago

3 0

252/25 or 10 2/25 or 10.08

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givi [52]

Answer:

30 students would have to go for the cost to be the same.

Step-by-step explanation:

Bus A: $40 + ($4 * 30) = $160

Bus B: $100 + ($2 * 30) = $160

7 0

3 years ago

What is the product of 7/16 and -6/13 I will make you the brainlest

mr_godi [17]

Answer:

$\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}$

Step-by-step explanation:

$\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}$ . First multiply 7*-6=-42.

Then do 16*13=208.

Simplify by dividing both by 2.

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5 0

3 years ago

a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect

PolarNik [594]

Number of dimes were 81 and number of quarters were 47

Solution:

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that There are 128 coins in all

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

Also given that collection of dimes and quarters is worth $19.85

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

$d \times 0.10 + q \times 0.25 = 19.85$

0.1d + 0.25q = 19.85 -------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 128 - q -------- eqn 3

Substitute eqn 3 in eqn 2

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

Thus number of dimes were 81 and number of quarters were 47

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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