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nadezda [96]
3 years ago
11

At a local school dance, the booster club is having a fundraiser selling pictures. Pictures without frames sell for $5, and with

a frame sell for $10. They made $875 selling 100 pictures. How many of the had frames?
Please show working
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0
Let p = pictures only
let f = pictures with frames

p + f = 100
5p + 10f = 875

Solve for one variable in the first equation then plug into the second

p = 100 - f
5(100 - f) + 10f = 875
500 - 5f + 10f = 875
500 + 5f = 875
5f = 375
f = 75

75 pictures with frames were sold
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Answer:

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Step-by-step explanation:

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3 years ago
Solve.
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<span>Solve.

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​ A x=−4±3√ ​2

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4 years ago
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Challenge A gold mine has two elevators, one for equipment and another for the miners. The
OLEGan [10]

Step-by-step explanation:

The equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface

ii. The miners elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e speed = \frac{distance}{time}

time

distance

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miners elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

= 44 seconds

So that, the distance of the elevator at this time is;

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 4 x 44

= 176

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time

distance

⇒ distance = speed x time

= 15 x 14

= 210

distance = - 210 feet

Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miners elevator is deeper than that of the equipment.

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