Surface Area of the figure is 1208 square centimeters
a=20
b=13
c=12
d=5
e=8
Top face:
A1=a×e=20×8
ae=160
Bottom face:
A2(a+2d)×e=(20+2×5)×8=(20+10)×8=30×8
(a+2d)e=240
Front face:
Rectangle
a×c=20×12=240
Triangle:
12c×d=12×12×5=6×5=30
A3Rectangle +2 triangles
240+2×30=240+60=300
(a+d)c=300
Slant face:
A4=b×e=13×8=104
be=104
Total surface area
A=A1+A2+2(A3+A4)
A1=160
A2=240
A3=300
A4=104
Thus,
A=160+240+2(300+104)
A=400+2(404)
A=400+808=1208
Surface Area of the figure is 1208 square centimeters
I think it would be 3 because if you divide 18/6=3
Answer:
Yes no yes yes
Step-by-step explanation:
Answer:
![r = \sqrt[3]{\dfrac{3V}{4 \pi}}](https://tex.z-dn.net/?f=%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B3V%7D%7B4%20%5Cpi%7D%7D%20)
Step-by-step explanation:
