What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
$4000
Step-by-step explanation:
so $2800 was the starting price
100%-30%=70%
So 2800=70%
2800/7=400
400=10%
400*10=$4000
<u>Explanation:</u>
a) First, note that the Type I error refers to a situation where the null hypothesis is rejected when it is actually true. Hence, her null hypothesis would be H0: mean daily demand of her clothes in this region should be greater than or equal to 100.
The implication of Type I error in this case is that Mary <u>rejects</u> that the mean daily demand of her clothes in this region is greater than or equal to 100 when it is actually true.
b) While, the Type II error, in this case, is a situation where Mary accepts the null hypothesis when it is actually false. That is, Mary <u>accepts</u> that the mean daily demand of her clothes in this region is greater than or equal to 100 when it is actually false.
c) The Type I error would be important to Mary because it shows that she'll be having a greater demand (which = more sales) for her products despite erroneously thinking otherwise.
X and Y are vertical angles, which mean they are the same.
The 3 inside angles need to equal 180 degrees, so solve for X:
X = 180 - 35 - 65 = 80 degrees.
Y = 80 degrees.
Answer:
C) It is the only solution to the system.
Step-by-step explanation:
3x + 3y = -30
2x + y = -17
3(-7) + 3(-3) = -30
-21 + -9 = -30
-30 = -30
True
2x + y = -17
2(-7) + (-3) = -17
-14 + -3 = -17
-17 = -17
True