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2 years ago

Solve the equation (x over x+2) - (4 over x-2) = 1

Mathematics

1 answer:

-BARSIC- [3]2 years ago

6 0

Answer:

$\frac{x}{x+2} - \frac{4}{x-2}=1\\or, \frac{x(x-2)}{(x+2)(x-2)} -\frac{4(x+2)}{(x+2)(x-2)}=1\\or, \frac{x^2-2x}{x^2-4} -\frac{(4x+8)}{x^2-4} =1\\or, \frac{x^2-2x-(4x+8)}{x^2-4} =1\\or, \frac{x^2-2x-4x-8}{x^2-4}=1\\or, {x^2-6x-8} =x^2-4\\or, -6x-8=-4\\or, 3x+4=2\\or, 3x = -2\\or, x =\frac{-2}{3}$

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If each month in reno had the same average rainfall as in august, what would the total number of millimeters be after 12 months

Inessa [10]

Answer:

12 times the August rainfall

Step-by-step explanation:

The total of 12 of the same value is 12 times that value. Multiply the August average by 12 to get your answer.

3 0

2 years ago

Evaluate the following using powers of ten rules. 104)1.042

Alinara [238K]

Answer:

0.0001042

Step-by-step explanation:

Power of tens rule states that if the denominator of a fraction has the positive power of 10, decimal in the numerator will be shifted to the left by the same number of places as exponent.

10⁴) 1.042 = $\frac{1.042}{10^4}$

In the denominator of the given fraction, exponent of 10 = +4

So the decimal in numerator will be shifted left by 4 places.

$\frac{1.042}{10^4}=0.0001042$

Therefore, answer is 0.0001042

5 0

2 years ago

A city planner designs a park that is a quadrilateral with vertices at J(-3,1), K(1,3), L(5,-1), and M(-1,-3). There is an entra

Ksivusya [100]

The Quadrilateral is JKLM,

let $M_{JK}, M_{KL}, M_{LM}, M_{JM},$ be the midpoints of JK, KL, LM and JM respectively.

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Given any 2 point P(m,n) and Q(k,l),

the coordinates of the midpoint of the line segment PQ are given by the formula:

$M_{PQ}=( \frac{m+k}{2} ,
\frac{n+l}{2})$ ,

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thus the coordinates of points $M_{JK}, M_{KL}, M_{LM}, M_{JM},$

are as follows:

$M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)$

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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

$|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}
}$

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thus the distances connecting the opposite entrances can be calculated as follows:

$|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5$

$|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39$

Thus the total distance of the paths joining the opposite entrances is

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)

Answer: 104 m

8 0

2 years ago

If a=58, then What is 59÷a?

algol [13]

To solve this problem we would plug 58 into the equation for a
Making the equation 59÷58

59÷58=1.0172413793103
Or
1.02

6 0

3 years ago

Solve for x. Show each step of the solution. 4.5(4 − x ) + 36 = 202 − 2.5(3x + 28)

IgorLugansk [536]

Answer:

Step-by-step explanation:

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4 0

2 years ago