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Lubov Fominskaja [6]
3 years ago
7

Pls help

Mathematics
1 answer:
N76 [4]3 years ago
5 0
A. 45/100 = 9/20
B. 9/20 = 27/x
9x=540
x = 6
She was assigned 60 problems (showing your work is practically justification in its on right)
C. 60-27
Yolanda still has 33 problems to do.
Hope this helped
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Write an equation of the line passes through the given points (6,-3),(1,2)
adoni [48]

Answer:

y = -x+3

Step-by-step explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

    = ( 2 - -3)/( 1 - 6)

   ( 2+3)/( 1-6)

   5/ -5

   -1

The slope is -1

We can use slope intercept form

y = mx+b  where m is the slope and b is the y intercept

y = -x+b

Substitute a point into the equation

2 = -1 +b

Add 1 to each side

2+1 = -1+1+b

3 = b

y = -x+3

6 0
3 years ago
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Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Unit rate of 357 miles In 6.3 hours
insens350 [35]
56.67 miles per hour
3 0
3 years ago
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If you simplify 4(3x + 8) - 3 . What will your answer be ?
scoundrel [369]
1.) Distribute 4 to (3x) & (8): 4*3x=12x, 4*8=32
2.) Rewrite the expression: 12x+32-3
3.) Combine like terms: 32-3=29
4.) Rewrite the final expression: 12x+29
Final Answer: <span>12x+29
Hope this helps!!
</span>
8 0
4 years ago
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can you plz help me with question 9 asp and if you get the answer plz show me how you got it or i will loose points on my homewo
olga2289 [7]
The answer is 123 I got the answer by multiplying length ×width×hight
6 0
3 years ago
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