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ehidna [41]
3 years ago
8

Write expressions in simplest form that represents the total amount in each situation

Mathematics
1 answer:
larisa86 [58]3 years ago
3 0
30 + 2x minutes a week.
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tangare [24]

one second the think I

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3 years ago
What is 1+1+2+3+4+5+6+7+8+9+10<br> Hi
JulsSmile [24]

Answer:

56

Step-by-step explanation:

1 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

 2 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

    4 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

      7 + 4 + 5 + 6 + 7 + 8 + 9 + 10

        11 + 5 + 6 + 7 + 8 + 9 + 10

         16 + 6 + 7 + 8 + 9 + 10

           22 + 7 + 8 + 9 + 10

             29 + 8 + 9 + 10

               37 + 9 + 10

                 46 + 10

                    56

Hope this helps!

Also hi

8 0
2 years ago
Question 5 options: Solve for y in terms of x: 12x−13=3y+b
Elden [556K]
Y = - b/3 +4x - 13/3

8 0
3 years ago
Let's Apply Solve for the surface area of the following figures. ​<br><br>please i need this rn​
Dafna1 [17]

Answer:

Step-by-step explanation:

1) Surface area of a square = s*s = 12*12 = 144 in

2) Surface area of a Cone =  A=πr(r+h2+r2) = 3.142*4(4+22*2+4*2) = 351.904 cm^2

3) S.A of a Cylinder =2πrh+2πr2 = 2*3.142*2*14 + 2*3.142*2*2 = 201.088 m^2

4) S.A of a square Pyramid = a^2 + 2a squareroot (a^2/4 + h^2) = 516.5m^2

5) S.A of a Sphere = 4*pie*r^2 = 4* 3.142*15^2 = 2827.8mm^2

3 0
2 years ago
A student who is trying to write a paper for a course has a choice of two topics, A and B. If topic A is chosen, the student wil
algol13

Answer:

P(Topic A) = 0.91

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A).

Step-by-step explanation:

If Topic A is chosen, 2 books will be ordered (n=2)

If topic B is chosen, 4 books will be ordered (n=4)

Probability that a book arrives in time (p) = 0.7

Probability that a book does not arrive in time (q) = 1 - p = 1 - 0.7 = 0.3

We will <u>use the binomial distribution</u> to find out which topic should the student choose to maximize the probability of writing a good paper. The binomial distribution formula is:

P(X=x) = ⁿCˣ pˣ qⁿ⁻ˣ

where p = probability of success

           q = probability of failure

           n = total no. of trials

           x = no. of successful trials

For Topic A, n = 2, p=0.7 and q=0.3. If topic A is chosen, the student will use at least half the books i.e. he will use either 1 or 2 books. So,

P(Topic A) = P(X=1) + P(X=2)

                 =²C₁ (0.7)¹(0.3)²⁻¹ + ²C₂ (0.7)²(0.3)²⁻²

                 = 0.42 + 0.49

P(Topic A) = 0.91

For topic B, n=4, p=0.7 and q=0.3. If topic B is chosen, the student will choose 2 or more books i.e. 2, 3 or 4 books.

P(Topic B) = P(X=2) + P(X=3) + P(X=4)

                  = ⁴C₂ (0.7)²(0.3)⁴⁻² + ⁴C₃ (0.7)³(0.3)⁴⁻³ + ⁴C₄ (0.7)⁴(0.3)⁴⁻⁴

                  = 0.2646 + 0.4116 + 0.2401

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A) as calculated above.

3 0
3 years ago
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