Question

Solve for the inequality -n-4<3

Answer 1

Question:-

$-n-4$

This is a inequality.We need to solve this inequality.

Solution:-

$\sf \longmapsto-n-4$

Firstly,Add 4 to two sides :-

$\sf \longmapsto - n - 4+4$

On Simplification:-

As (-) and (+) equals to (-),It would be 4-4.Answer is 0.

$\sf \longmapsto - n - 0 < 7$

$\sf \longmapsto \: - n < 7$

Then, Divide both sides by -1 :·-

$\sf \longmapsto \: \dfrac{ - n}{ - 1} < \dfrac{7}{ - 1}$

On Simplification :-

If the denominator is 1, it means that there is no value of 1 in the fraction.

$\sf \longmapsto \: \dfrac{ \cancel- n}{ \cancel- 1} < \dfrac{ \cancel7}{ - \cancel1}$

$\sf \longmapsto \: n > -7$

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Henceforth, the value of the inequality is :-

$\boxed{\tt \: n > - 7}$

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I hope this helps!

Please let me know if you have any questions.

~MisterBrian