Remember that finding common denominators is only one of the strategies for comparing fractions
One can prove congruence through transformation if they have the same shape and size.
The congruency postulates include:
- SSS - Side-Side-Side
- SAS - Side-Angle-Side
- ASA- Angle-Side-Angle
- AAS - Angle-Angle-Side
- RHS - Right angle-Hypotenuse-Side
<h3>What is congruence?</h3>
In geometry, it should be noted that two figures are congruent if they have the same shape and size.
In this case, if two angles and a non-included side of one triangle are equal to two angles and a non-included side of another triangle, then the triangles are congruent.
One can prove triangle congruence using congruency postulates by using the SSS theorem( side side side theorem).
It should be noted that the congruence postulate is used to illustrate that the triangles are equal.
Learn more about congruence on:
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Answer:
0 ≤ an ≤ bn
The series ∑₁°° bn converges
The series ∑₁°° an converges by comparison to ∑₁°° bn.
0 ≤ an ≤ bn
The series ∑₁°° bn diverges
The comparison test is inconclusive for our choice of bn.
Step-by-step explanation:
an = 1 / (n² + n + 3) and bn = 1 / n²
The numerators are the same, and the denominator of an is greater than the denominator of bn. So 0 ≤ an ≤ bn.
bn is a p series with p > 1, so it converges.
Since the larger function converges, the smaller function also converges.
an = (3n − 1) / (6n² + 2n + 1) and bn = 1 / (2n)
If we rewrite bn as bn = (3n − 1) / (6n² − 2n), we can tell that when the numerators are equal, the denominator of an is greater than the denominator of bn. So 0 ≤ an ≤ bn.
bn is a p series with p = 1, so it diverges.
The larger function diverges. We cannot conclude whether the smaller function converges or diverges.
The picture is missing tell me what it is I will answer in comments
Answer:
Below.
Step-by-step explanation:
nth term = a1 r^(n-1)
= 8(-2)^(n-1)
When n = 16 it is
8*-2^15
= -262144.
