Answer:
(x+y)/xy or (1/x + 1/y) portion of the leaves
Step-by-step explanation:
Let the total work done to rake the leaves be a for representation.
Thus,
given Maya takes x minutes to rake the leaves
thus,
work done by may in x minutes = a
dividing both side by x
work done by maya in x/x = 1 minutes = a/x
similarly
given Calra takes y minutes to rake the leaves
thus,
work done by may in y minutes = a
dividing both side by y
work done by maya in y/y = 1 minutes = a/y
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Total work done by both in 1 minutes = a/x + a/y = a(1/x+1/y) = a(x+y)/xy
Thus, if a is the total work , then they do (x+y)/xy of a work in one minute.
Thus, (x+y)/xy portion of leaves do they rake in one minute if they work together.
Answer:
Correct option is B.
Step-by-step explanation:
Given the radius of circle and the angle in sector we have to find the area of shaded region i.e minor sector.
∴ Area of sector is 
Correct option is B.
Answer:
52 ft
Step-by-step explanation:
For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:
(24 ft)·(24 ft) = 576 ft^2
Then the missing segment length (DX) of the diameter chord is ...
DX·(36 ft) = 576 ft^2
DX = (576 ft^2)/(36 ft) = 16 ft
So, the total length of the diameter chord is ...
DX +XL = 16 ft + 36 ft
DL = 52 ft
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We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.
Answer:
Step-by-step explanation:
ANSWER:
average = total distance / time
average = 200/25 = 8 m /s
